Activity 1.10 Class 10 Science

 This activity explains the double displacement reaction between sodium sulphate and barium chloride.

Double Displacement Reaction

Caution: This activity needs the teacher’s assistance.

 Aim of The Activity

To demonstrate the double displacement reaction and formation of precipitate

Procedure

1)  Take about 3 ml of sodium sulphate solution in a test tube.

2)  In another test tube. take about 3 ml of barium chloride solution.

3)  Mix the two solutions.

4)  What do you observe?

Observation

A double displacement reaction occurs between sodium sulphate and barium chloride. An  insoluble white solid substance forms. This solid substance is barium sulphate.

Explanation

When sodium sulphate and barium chloride react, a double displacement reaction takes place.

After the exchange of ions between compounds, a white solid substance of barium sulphate is formed and sodium chloride remains in the solution.

Conclusion

The insoluble white substance formed is known as a precipitate.

 

       Na₂SO₄(aq) + BaCI₂(aq) →     BaSO₄(s) + 2NaCI(aq) 

This is also known as Precipitation Reaction.

Frequently Asked Questions

 

1.   What is a precipitate?

Ans – Precipitate is an insoluble solid substance.

2.   What is a precipitation reaction?

Ans – The reaction in which an insoluble solid substance is formed is called a precipitation reaction.

3.   What is the chemical name of the precipitate formed during the reaction?

Ans- Barium sulphate

4.   Write the chemical formula of the precipitate formed during the reaction?

And – BaSO4

5.   Write the chemical reaction that takes place in activity 1.10?

Ans - Na₂SO₄(aq) + BaCI₂(aq) →     BaSO₄(s) + 2NaCI(aq) 

 

Related Topics for you

1.   Activity 1.9  Class 10 Science

2. Solution of Chemical Reactions and Equations

3. MCQ Questions of Chapter 1 

4. Extra Questions of Chapter 1