All Solutions

Important

Wednesday, November 13, 2024

Activity 1.2 Class 10 Science

 



Caution: This activity needs the teacher’s assistance.

Activity 1.2 Class 10 Science


Material Required

1.  Lead nitrate solution

2.  Potassium iodide solution

3. Test tubes


Activity (Procedure)

First of all, we take a test tube and pour some amount of lead nitrate solution into it.

Now we add some amount of potassium iodide

 solution into the test tube.


Activity 1.2 Class 10th Science



What do you observe?



Observation

After mixing the two solutions, we see a yellow precipitate of lead iodide formed.


Pb (NO3)2 (aq)    + 2KI (aq) → PbI2 (s)  + 2KNO3 (aq)


Explanation

During the activity, a double displacement reaction takes place between lead nitrate and potassium iodide solution. There is an exchange of ions between both compounds and two new compounds are formed.

During this activity, a yellow-colored precipitate is formed.

 A precipitate is an insoluble solid substance.    


Conclusion: 

This activity shows a double displacement reaction between lead nitrate and potassium iodide solution.

It can also be called a precipitate reaction as an insoluble solid substance[Precipitate]  formed during the activity.



Queries based on activity 1.2 Class 10 Science


1. Give the chemical name of the precipitate formed during this activity.
Ans,-  Lead iodide (PbI2 )

2. What is a precipitate?
Ans.-  A precipitate is an insoluble substance formed during a chemical reaction.

3. What is a precipitation reaction?
Ans.-  The reaction in which an insoluble substance is formed is called a precipitate and the reaction is called a precipitation reaction.


4. What is the colour of the precipitate formed during the activity?
Ans – A yellow-coloured precipitate is formed.


5. What are the reactants in activity 1.2?
Ans – Lead nitrate and potassium iodide solution.


6. Write the chemical equation for the reaction takes place in the activity?
Ans – Pb(NO3)2 + 2KI →PbI2(s) + 2KNO3

7. What are the products formed in this activity?
Ans – Lead iodide and potassium nitrate 


8. What is the conclusion of activity 1.2 Class 10 Science?
Ans – In this activity, a double displacement reaction takes place


9. What is the chemical formula of lead nitrate?
Ans – Pb(NO3)2


10. What are the characteristic features of the activity?
Ans – Formation of insoluble solid substance (precipitate)





 









No comments:

Post a Comment