Find position, nature and height of image of object placed in front of concave mirror

Today we will learn class 10 physics numericals of chapter light -Reflection and Refraction. The following question is related to the spherical mirror.

After reading the solution, you can watch the video to understand the question properly.

An object 2 cm high is placed at a distance of 20 cm in front of a concave mirror of a focal length of 15 cm. Find the position, nature, and height of the image formed.

Given values 

Height of object(h)= 2cm

Object distance (u)= -20 cm

Focal length (f)= -15 cm

Image distance(v)=?

Height of image (h’)=?

[focal length of concave mirror is negative]

(i) Position of image 

  `1/u+  1/v=1/f`

 

  `1/(-20)+  1/v=1/(-15)`

 

  `1/v=1/(-15)-  1/20` 

  `1/v=(-4  +3 )/60`

 

   `1/v=(-1)/60`

 

  `v  =   -60 cm`

 

  `v  =   -60 cm`

 

So image will be formed at a distance of 60 cm from the

(-) sign of v shows that an image formed is real and inverted.

(ii) height of the image

   `h^'/h=-  v/u`

 

    `h^'/2=-  ((-60))/((-20))`

 

   `h^'=-3 ×2= -6 cm`

 

(-) sign of height of the image shows the image is real and inverted.

Watch the video to understand the Numerical question 

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1. Numerical question