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Saturday, December 9, 2023

Class 10 Physics Electricity Numericals

Today we are going to solve class 10 physics electricity numericals based on the heating effect of electric current 


      

Class 10 Physics Electricity Numericals

Numerical Problems based on Heating effect of current


  Q1. How much heat will a device of 15 W produces in one minute if it is connected to a battery of 15 Volt.

   

       Given values


       P =15W

       V = 15 volt

       t  = 1 min  =  60 s

      

       Solution

    

       H= P × t


       H = 15× 60 =900 J

    

   Q2.. 1 kJ hat is produced each second in 50 Ohm resistor. Calculate the potential difference across the resistor.

   

       Given values


       H=  1kJ =1000J

       Time(t) =1 s

       Resistance (R) =50 Ohm

       Voltage (V) =?

    

       Solution 

         `H=I^2 Rt`


        `1000=I^2  ×50 ×1`


        `I^2=  1000/50=20`


       `I= √20 = 4.47A`


       So, the potential difference across the resistor 


         V=IR


         V= 4.47 × 50 =223.5 volt

      

  Q3. A heater of resistance 10 Ohm draws 10 A current from an electric source for 2 hours. Calculate the heat produced in the heater.


      Given values


       Resistance (R ) = 10 Ohm

      Current (I) = 10 A

      Time (t) = 2 hours = 2 × 60 ×  60 =7200 s

      Heat (H) =?


      Solution 


       `H=I^2 Rt`


       `H=10^2   ×10 ×7200`


        `H= 72 × 10^5` J


   Q4. 100 Joule of heat is produced each second in 10 Ohm resistance. find the potential difference across the resistor.


       Given values


       Heat (H) =100J

      Time (t) =  1s

      Resistance (R) = 10 Ohm

      Potential difference (V) =?

 

       Solution 


       V=IR


     In the above formula we need the value of current (I) so at first we must find the value of I from the given values


       `H=I^2 Rt`


       `I= √H/Rt`


       `I= √100/(10× 1)`

 

      `I= √10`


        `I= 3.16` A


     Now we can find the value of the potential difference


       V=IR


       V = 3.16 ×10

    

       V= 31.6 volt


  Q5. How much energy is given to 10 coulomb charges passing through 15 volt battery?


      Given values

      Charge (Q) = 10 Coulomb

      Voltage (V) =15 volt

      Energy (E) =?

    

    Solution


       E= VQ


       E = 15× 10 = 150 J


    

  Q6. Find the heat produced in the following combination of resistors if the current is drawn for 10 seconds.

     


     Given values 


R1=  2 Ohm

R2 =  2 Ohm

Potential difference (V) =10 volt

Time (t)= 10 s

Heat (H) =?


 Solution 

  `H= V I t`


We will have to find the value of the current (I)


 `R = R_1 + R_2`


  R = 2 +2 =4 Ohm


   `I=V/R`


 `I=10/4=2.5` A


 `H= V I t`


`H= 10 ×2.5 ×10`


`H = 250 J`



      ✅Related Topics

    1.  Derive the formula of work done when current flows through a conductor or resistor

    2. Numerial Based on Electric Current 

     3. Solved Numeicals on Electricity 


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