Activity 11.16 Class 9 Science Chapter 11
Activity 11.16 Class 9 Science
belongs to Chapter 11 Work and Energy Class 9 Science. You will get a
complete solution with an explanation and conclusion. After reading activity
11.16, you will be able to answer the questions based on the activity.
Activity 11.16 Class 9 Science Work and Energy
You are suggested to study NCERT activity 11.16 class 9 science
chapter 11Work and Energy explanation with a conclusion so that you can attempt
questions based on activity 11.16 class 9 science.
Activity 11.16 Class 9 Science
· Consider
two children, say A and B. let us say they weigh the same. Both start climbing
up a rope separately. Both reach a height of 8m. let us say A takes 15 s while
B takes the 20s to accomplish the task.
· What
is the work done by each?
· The
work done is the same. However, A has taken less time than b to do the work.
· Who
has done more work in a given time, say in 1 s?
Calculation and explanation of Activity 11.16 Class 9 Science
Both the children climbing up means work done is against gravity.
W=mgh
Let each child weighs 25 kg
Work done by child A in climbing a height of 8m
`W_A= mgh`= 25×10×8 = 2000J
Work done by the child B in climbing a height of 8m
`W_B= mgh`= 25×10×8 = 2000J
So we can say
Work done by child A =Work done by child B
Now, work done per unit time by child A
(Note: rate of doing work is known as power)
`P_A=W_A/t`= 2000/15=1333.3W
work done per unit time by child A
`P_B=W_B/t`= 2000/20=100W
So, the power of child A is more than that of child B.
Conclusion of activity 11.16 class 9 science
This activity explains the rate of doing work.
Related Topics
1. Activity 11.17 Class 9 Science
2. Activity 11.15 Class 9 Science
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