All Solutions

Important

Wednesday, June 29, 2022

NCERT Class 10 Science Activity 12.6 Solution Electricity | Activity 12.6 Class 10 Science Electricity

 NCERT Class 10 Science Activity 12.6 Solution Electricity | Activity 12.6 Class 10 Science Electricity


In this article, we will discuss activity 12.6 class 10 science. You will find a complete explanation with a conclusion.

After studying this activity 12.6 Class 10 Science Electricity, you will be able to solve Questions of Chapter 12 Electricity.

 

 

Activity 12.6 Class 10 Science

    ·     Make a parallel combination, XY, of three resistors having resistances R1, R2, and R3 respectively. Connect it with a battery, a plug key, and an ammeter. Also, connect a voltmeter in parallel with the combination of resistors.


   ·     Plug the key and note the ammeter reading. Let the current be I. also take the voltmeter reading. It gives the potential V  across the combination. The potential differences across each resistor are also v. this can be checked by connecting the voltmeter across each individual resistor.

      

Activity 12.6 Class 10 Science Electricity

    ·     Take out the plug from the key. Remove the ammeter and voltmeter from the circuit. Insert the ammeter in series with the resistor R1. Note the ammeter reading I1.

     

NCERT Class 10 Science Activity 12.6 Solution Electricity

    ·     Similarly, measure the currents through R2 and R3. Let these be I2 and I3 respectively. What is the relationship between I, I1, I2, and I3.


     Observation Activity 12.6 Class 10 Science

 

The total current I is equal to the sum of the current through each branch of the combination.

I= I1 +I2 +I3    (i)

The potential difference across each resistor is same.

Explanation Activity 12.6 Class 10 Science

 

The equivalent resistance of the parallel combination of resistors is Rp.

According to Ohm’s law

`I=frac{V}{R_P}`


So for each resistor

`I_1=frac{V}{R_1}`


`I_2=frac{V}{R_2}`


and


`I_3=frac{V}{R_3}`



From the equation (i)

`frac{V}{R_P}=frac{V}{R_1} + frac{V}{R_2} + frac{V}{R_3}`


 `frac{1}{R_P}V=V(frac{1}{R_1} + frac{1}{R_2} + frac{1}{R_3})`


 `frac{1}{R_P}=frac{1}{R_1} + frac{1}{R_2} + frac{1}{R_3}`



Conclusion Activity 12.6 Class 10 Science

 

 When a number of resistors are connected in parallel then the total current in the circuit is divided into different resistors while the potential difference remains the same.

Total current 

I= I1 +I2 +I3    

  

Related Topic for you


1. First  Activity-  Activity 12.1 Class 10 Science

2. Previous Activity -  Activity 12.5 Class  10 Science

3. Solution of Chapter 12 Electricity

4. Extra Questions of Chapter 12 Electricity

5. MCQ Questions of Chapter 12 Electricity