NCERT Class 10 Science Activity 12.6 Solution Electricity | Activity 12.6 Class 10 Science Electricity
In this article,
we will discuss activity
12.6 class 10 science.
You will find a complete explanation with a conclusion.
After studying
this activity 12.6 Class 10 Science Electricity, you will be able to
solve Questions of Chapter 12 Electricity.
Activity
12.6 Class 10 Science
·
Make a parallel
combination, XY, of three resistors having resistances R1, R2,
and R3 respectively. Connect it with a battery, a plug key, and an
ammeter. Also, connect a voltmeter in parallel with the combination of resistors.
·
Plug the key and note
the ammeter reading. Let the current be I. also take the voltmeter reading. It gives
the potential V across the combination. The
potential differences across each resistor are also v. this can be checked by
connecting the voltmeter across each individual resistor.
·
Take out the plug
from the key. Remove the ammeter and voltmeter from the circuit. Insert the ammeter
in series with the resistor R1. Note the ammeter reading I1.
·
Similarly, measure
the currents through R2 and R3. Let these be I2
and I3 respectively. What is the relationship between I, I1, I2, and
I3.
Observation Activity 12.6 Class 10 Science
The total current I is equal
to the sum of the current through each branch of the combination.
I= I1 +I2
+I3 (i)
The potential difference
across each resistor is same.
Explanation Activity
12.6 Class 10 Science
The equivalent resistance of
the parallel combination of resistors is Rp.
According to Ohm’s law
`I=frac{V}{R_P}`
So for each resistor
`I_1=frac{V}{R_1}`
`I_2=frac{V}{R_2}`
and
`I_3=frac{V}{R_3}`
From the equation (i)
`frac{V}{R_P}=frac{V}{R_1} + frac{V}{R_2} + frac{V}{R_3}`
`frac{1}{R_P}V=V(frac{1}{R_1} + frac{1}{R_2} + frac{1}{R_3})`
`frac{1}{R_P}=frac{1}{R_1} + frac{1}{R_2} + frac{1}{R_3}`
Conclusion Activity
12.6 Class 10 Science
When a number of resistors are connected in
parallel then the total current in the circuit is divided into different resistors
while the potential difference remains the same.
Total current
I= I1 +I2 +I3
Related Topic for you
1. First Activity- Activity 12.1 Class 10 Science
2. Previous Activity - Activity 12.5 Class 10 Science
3. Solution of Chapter 12 Electricity
4. Extra Questions of Chapter 12 Electricity