NCERT Class 10 Science Activity 12.5 Solution Electricity | Activity 12.5 Class 10 Science Electricity
In this article,
we will discuss activity
12.5 class 10 science.
You will find a complete explanation with a conclusion.
After studying
this activity 12.5 Class 10 Science Electricity, you will be able to
solve Questions of Chapter 12 Electricity.
Activity
12.5 Class 10 Science
·
Join three resistors of
different values in series. Connect them with a battery, an ammeter, and a plug
key. You may use the resistors of values like 1Ω,2Ω,3Ω, etc., and a battery of 6V
for performing this activity. Insert a voltmeter across the ends of X and Y of the
series combination of three resistors.
·
Plug the key in the circuit and note the voltmeter reading. It
gives the potential difference across the series combination of resistors. Let it
be V. now measure the potential difference across the two terminals of the
battery. Compare the two values.
·
Take out the plug key and disconnect the voltmeter.
Now insert the voltmeter across the ends of X and P of the first resistors.
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·
Plug the key and measure
the potential difference across the first resistor. Let it be V1.
·
Similarly measure the potential
difference across the other two resistors, separately. Let these values be V2 and V3
respectively.
·
Deduce a relationship between
V, V1, V2, and V3
Observation Activity 12.5 Class 10 Science
The potential difference of
the combination is equal to the potential difference across two terminals of
the battery.
Explanation Activity
12.5 Class 10 Science
According
to Ohm’s law
R=R1+R3
+R3
R= 1 +2 +3 =6 Ω
i. Potential difference across the ends of three resistors separately.
Potential difference
across the ends of resistors of 1Ω
V1=R1I
=1×1=1volt
Potential difference
across the ends of resistors of 2Ω
V2=R2I
=2×1=2volt
Potential difference
across the ends of resistors of 3Ω
V3=R3I
=3×1= 3volt
V=V1 +V2+V3
Total Potential difference
V= 1 +2 +3 =6 volt
Total potential differences are equal to the potential difference of battery.
Conclusion
The potential difference across
the ends of all three resistors is different, but the sum of all potential
differences is equal to the potential difference across the ends of the source.
In the series combination, the potential
difference of the battery gets divided among the individual resistors connected
in the series.
Related Topic for you
1. Next Activity- Activity 12.6 Class 10 Science
2. Previous Activity - Activity 12.4 Class 10 Science
3. Solution of Chapter 12 Electricity
4. Extra Questions of Chapter 12 Electricity
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