In this article, we will discuss activity 12.1 class 10 science. You will find a complete explanation with a conclusion. After studying this activity 12.1 Class 10 Science Electricity, you will be able to solve Questions of Chapter 12 Electricity.
Explain NCERT Class 10 Science Activity 12.1 Solution Electricity| Activity 12.1 Class 10 Science Electricity
Activity
12.1 Class 10 Science
Set
up a circuit as shown in the figure, consisting of a nichrome wire XY of length,
say 0.5m, an ammeter, a voltmeter, and iron metals.
 |
| circiut |
·
First use only one cell as the source in the circuit. Note
the reading in the ammeter I, for the current and reading of the voltmeter V
for the potential difference across the nichrome wire ‘XY’ in the circuit. Tabulate
them in the table given ahead.
·
Next connect two cells in the circuit and note the respective
readings of the ammeter and voltmeter for the values of current through the nichrome
wire and potential difference across the nichrome wire.
·
Repeat the above steps using three cells and then four cells
in the circuit separately.
·
Calculate the ratio of V to I (for each pair of potential
difference V and current I)
|
S.No. |
Number
of cells used in the circuit |
Current
through the nichrome wire I(amp) |
Potential
difference across the nichrome wire V(volt) |
V/I (volt/amp) |
|
1 |
|
|
|
|
|
2 |
|
|
|
|
|
3 |
|
|
|
|
|
4 |
|
|
|
|
·
Plot a graph between V and I and observe the nature of the graph.
Explanation Activity
12.1 Class 10 Science
When
we increase the cell or battery in the circuit step by step, the potential difference
increases across the wire XY.
The potential difference is directly proportional to the current(V∝I) flowing to it.
Reading
in voltmeter and ammeter increases respectively.
We
can see the reading in the following table
|
S.No. |
Number
of cell used in the circuit |
Current
through the nichrome wire I(amp) |
Potential
difference across the nichrome wire V(volt) |
V/I (volt/amp) |
|
1 |
1 |
0.30 |
1.5 |
5 |
|
2 |
2 |
0.60 |
3.0 |
5 |
|
3 |
3 |
0.90 |
4.5 |
5 |
|
4 |
4 |
1.20 |
6.0 |
5 |
Observation Activity
12.1 Class 10 Science
We
observe that the ratio V/I is approximately the same so the graph between V and I is
a straight line.
A
straight-line graph shows that as the current through the wire XY increases, the
potential difference across the wire increases. This is called Ohm’s law.
Conclusion Activity
12.1 Class 10 Science
The
ratio of V and I is a constant and this constant ratio is called Resistance. Hence
Ohm’s law is proved.
Related Topic for you
1. Next Activity- Activity 12.2 Class 10 Science
2. Solution of Chapter 12 Electricity
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