If you are looking for NCERT Science Class 10 Chapter 5 Activity solutions, then you are at the right place. In this post, you will find NCERT Activity 5.5 Class 10 Science Explanation with conclusion.
NCERT Activity 5.5 Class 10 Science Explanation with conclusion
You are
suggested to study NCERT activity 5.5 class 10 science explanation with a conclusion so that you can attempt questions based on activity 5.5 class 10
science.
Class 10 Science Chapter 5 Periodic Classification of Elements
Activity 5.5 Class 10 Science
· If you look at the long form of the Periodic Table, you will find that the elements Li, Be, B, C, N, O, F and Ne are present in the second period. Write down their electronic configuration.
· Do these elements also contain the same number of valence electrons?
· Do they contain the same number of shells?
Discussion –
The electronic configuration of the elements of the second period is given in the
table shown below:
|
Elements |
Li |
Be |
B |
C |
N |
O |
F |
Ne |
|
Electronic Configuration |
K,L 2, 1 |
K,L 2, 2 |
K,L 2, 3 |
K,L 2, 4 |
K,L 2, 5 |
K,L 2, 6 |
K,L 2, 7 |
K,L 2, 8 |
· Yes, on observing these elements they do not contain the same number of valence electrons. The number of valence electrons actually increases from 1 to 8.
Valence electron of lithium (Li) =1
Valence electron of beryllium (Be) =2
Valence electron of boron (B) =3
Valence electron of carbon (C) =4
Valence electron of nitrogen (N) =5
Valence electron of oxygen(O) =6
Valence electron of fluorine (F) =7
Valence electron of neon (Ne) =0
· Yes, all these elements contain the same number of shells, i.e., K and L.
Related Topics for You
1. Activity 5.6 Class 10 Science
2. Activity 5.4 Class 10 Science
3. NCERT Solutions of Class 10 Science Chapter 5
5. Solutions of Class 10 Science all chapters
.webp)
