NCERT Activity 4.9 Class 10 Science Explanation with conclusion

If you are looking for NCERT Science Class 10 Chapter 4 Activity solutions, then you are in the right place. In this post, you will find NCERT Activity 4.9 Class 10 Science Explanation with conclusion.

NCERT Activity 4.9 Class 10 Science Explanation with conclusion

You are suggested to study NCERT activity 4.9 class 10 science explanation with conclusion so that you can attempt questions based on the activity 4.9 class 10 science.

 

Chapter 4 - Carbon and its Compounds

 

Activity 4.9 Class 10 Science

·      Set up the apparatus as shown in chapter 2, activity 2.5

·      Take a spatula full of sodium carbonate in a test tube and add 2 ml of dilute ethanoic acid.

·      What do you observe?

·      Pass the gas produced through freshly prepared lime water what do you observe?

·      Can the gas produced by the reaction between ethanoic acid and sodium carbonate be identified by this test?

Discussion and Conclusion: On the addition of sodium carbonate to a dilute solution of ethanoic acid, a brisk effervescence due to the evolution of carbon dioxide (CO₂) gas is produced.

2CH₃COOH +  Na₂CO₃ → 2CH₃COONa +H₂O +CO₂

When carbon dioxide gas is passed through freshly prepared lime water, it changes lime water milky due to the formation of insoluble calcium carbonate.

 

    Same observations are noted in the replacement of sodium bicarbonate instead of sodium carbonate.

CH₃COOH +  NaHCO₃ → CH₃COONa +H₂O +CO₂

Related Topics - 

1. Next  activity - Activity 4.10 Class 10 Science

2. Previous activity - Activity 4.8 Class 10 Science

3. Solution of Chapter 4 Carbon and its Compounds

4. MCQ Questions of Chapter 4

5. Extra Questions of Chapter 4

6. Solutions of Class 10 Science all chapters