In this post, you will learn a complete explanation of activity 1.5class 10 science that belongs to Chapter 1 Chemical Reactions and Equations. You can also go through Activity 1.6 of Chapter 1 Chemical Reactions and Equations.
Activity 1.5 Class 10 Science
Caution: This activity
needs the teacher’s assistance. don’t point
the mouth of the test tube towards anybody.
Activity- Take about 2g of ferrous sulphate crystals in a dry boiling tube.
· Note the colour of the ferrous sulphate crystals.
· Heat the boiling tube over the flame of a burner or spirit lamp as shown in figure below.
· Observe the colour of the crystals after heating.
Observation
Ferrous sulphate crystals lose water when heated and the colour of crystals
changes.
Ferrous sulphate crystals are green in colour and have 7 molecules of crystalline water.
FeSO4.7H2O(s) → FeSO4(s) + 7H2O(g)
Conclusion
When ferrous sulphate further decomposes, it gives a reddish-brown residue of
ferric oxide and fumes of sulphur dioxide and sulphur trioxide evolve.
2FeSO4(s) → Fe2O3(s) + SO2(g) +SO3(g)
The decomposition of ferrous sulphate occurs in the above reaction.
Watch the video to understand activity 1.5
Questions based on Activity 1.5 Class 10 Science
1. What is the colour of ferrous sulphate crystals?
Ans.- Ferrous sulphate crystals are green in colour.
2. How many water molecules are present in one molecule of ferrous sulphate?
Ans. Seven water molecules (FeSO4.7H2O)
3. Which gases evolve when ferrous sulphate is heated?
Ans. Sulphur dioxide(SO2) and Sulphur trioxide(SO3)
4. Name the chemical reaction involved in heating ferrous sulphate.
Ans. Decomposition reaction
5. Name the substance that remains in the test tube as residue.
Ans. – Ferric oxide (Fe2O3)
MCQs based on Activity 1.5 Class 10 Science
Related Topics for you
1. Activity 1.6 Class 10 Science
2. Activity 1.4 Class 10 Science
2. Solution of Chemical Reactions and Equations
4. Extra Questions of Chapter 1